Voltage Divider


Divided voltage can be found from the following equation.

Input Values. Enter the Given:



Result:





Enter Standard Resistance Value, R1, and Verify VOUT





The following is a project under a permanent construction

Superposition is a theorem that can be applied to any linear circuit. Essentially, when there are independent sources, the voltages and currents resulting from each source can be calculated separately, and the results are added algebraically. This simplifies the calculations because it eliminates the need to write a series of loop or node equations.

 

                   1
                 -----
                  sC1               1
 VA(VB = 0) = ----------- V1 = ------------ V1
                1            	1 + s C1 R1
              ----- + R1
               sC1 


                   1
                 -----
                  sC1                1
 VA(V1 = 0) = ----------- VB = -------------- VB
                1            	1 + s^2 C1 L1
              ----- + sL1
               sC1 

                                    V1            VB
 VA = VA(VB = 0) + VA(V1 = 0) = ---------- + --------------
                                 1 + sC1R1    1 + s^2 C1 L1

 s^2 = (jw)^2 = -w^2

                                    V1            VB
 VA = VA(VB = 0) + VA(V1 = 0) = ---------- + --------------
                                 1 + sC1R1    1 - w^2 C1 L1



                                       V1                  VB
 VA = VA(VB = 0) + VA(V1 = 0) = -------------------- + --------------
                                (1 + (wC1R1)^2)^1/2    1 - w^2 C1 L1




Two-Port Modeling of Amplifiers

Input Values Impedance Calculator:




Result: